5[r-1]=2(r-4)-6

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Solution for 5[r-1]=2(r-4)-6 equation:


Simplifying
5[r + -1] = 2(r + -4) + -6

Reorder the terms:
5[-1 + r] = 2(r + -4) + -6
[-1 * 5 + r * 5] = 2(r + -4) + -6
[-5 + 5r] = 2(r + -4) + -6

Reorder the terms:
-5 + 5r = 2(-4 + r) + -6
-5 + 5r = (-4 * 2 + r * 2) + -6
-5 + 5r = (-8 + 2r) + -6

Reorder the terms:
-5 + 5r = -8 + -6 + 2r

Combine like terms: -8 + -6 = -14
-5 + 5r = -14 + 2r

Solving
-5 + 5r = -14 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.
-5 + 5r + -2r = -14 + 2r + -2r

Combine like terms: 5r + -2r = 3r
-5 + 3r = -14 + 2r + -2r

Combine like terms: 2r + -2r = 0
-5 + 3r = -14 + 0
-5 + 3r = -14

Add '5' to each side of the equation.
-5 + 5 + 3r = -14 + 5

Combine like terms: -5 + 5 = 0
0 + 3r = -14 + 5
3r = -14 + 5

Combine like terms: -14 + 5 = -9
3r = -9

Divide each side by '3'.
r = -3

Simplifying
r = -3

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